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Find the distance of thez-axis from the image of the point `M(2-3,3)`in the plane `x-2y-z+1=0.` |
Answer» Correct Answer - `1` If image of point `(2, -3, 3)` in the plane `x-2y-z+1=0` is `(a, b, c)`, then `(a-2)/(1)= (b+3)/(-2)= (c-3)/(-1)= (-2(2-2(-3)-3+1))/((1)^(2)+ (-2)^(2)+ (-1)^(2)) = -2` Hence, the image is `(0, 1, 5)` Obviously distance of image of the point from the `z`-axis is 1. |
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