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Find the domain and range of each of the following real valued functions : f(x) = √(x2-16)f(x) = \(\sqrt{x^2-16}\) |
Answer» f(x) = √(x2-16) We know, The square of a real number is never negative. Clearly, f(x) takes real values only when x2 – 16 ≥ 0 ⇒ x2 – 42 ≥ 0 ⇒ (x + 4)(x – 4) ≥ 0 ⇒ x ≤ –4 or x ≥ 4 ∴ x ∈ (–∞, –4] ∪ [4, ∞) Thus, Domain of f = (–∞, –4] ∪ [4, ∞) When x ∈ (–∞, –4] ∪ [4, ∞), We have, x2 – 16 ≥ 0 Hence, \(\sqrt{x^2-16}\) ≥ 0 ⇒ f(x) ≥ 0 ∴ f(x) ∈ [0, ∞) Thus, Range of f = [0, ∞) |
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