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Find the domain and range of each of the following real valued functions : f(x) = √(x-1) |
Answer» f(x) = √(x-1) We know, The square of a real number is never negative. Clearly, f(x) takes real values only When x – 1 ≥ 0 ⇒ x ≥ 1 ∴ x ∈ [1, ∞) Thus, Domain of f = [1, ∞) When x ≥ 1, We have, x – 1 ≥ 0 Hence, \(\sqrt{x-1}\) ≥ 0 ⇒ f(x) ≥ 0 ∴ f(x) ∈ [0, ∞) Thus, Range of f = [0, ∞) |
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