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Find the domain and range of each of the following real valued functions : f(x) = √(x-3) |
Answer» f(x) = √(x-3) We know, The square of a real number is never negative. Clearly, f(x) takes real values only when x – 3 ≥ 0 ⇒ x ≥ 3 ∴ x ∈ [3, ∞) Thus, Domain of f = [3, ∞) When x ≥ 3, We have x – 3 ≥ 0 Hence, \(\sqrt{x-3}\) ≥ 0 ⇒ f(x) ≥ 0 ∴ f(x) ∈ [0, ∞) Thus, Range of f = [0, ∞) |
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