1.

Find the domain and the range of each of the following real function: f(x) = \(\frac{x^2-9}{x-3}\)

Answer»

Given: f(x) = \(\frac{x^2-9}{x-3}\)

Need to find: Where the functions are defined. 

To find the domain of the function f(x) we need to equate the denominator of the function to 0. 

Therefore, 

x – 3 = 0 

⇒ x = 3 

It means that the denominator is zero when x = 3 

So, the domain of the function is the set of all the real numbers except 3. 

The domain of the function, Df(x) = (- ∞, 3) ∪ (3, ∞). 

Now if we put any value of x from the domain set the output value will be either (-ve) or (+ve), but the value will never be 6 

So, the range of the function is the set of all the real numbers except 6. 

The range of the function, Rf(x) = (-∞, 6) ∪(6, ∞).



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