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Find the domain of `f(x)=sqrt(sinx)+sqrt(16-x^2)` |
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Answer» Correct Answer - `[-4,-pi] cup [0,pi]` `f(x)=sqrt(sinx)+sqrt(16-x^(2))` or ` sinx ge 0 " and " 16-x^(2) ge 0` or `2n pi le x le (2n+1)pi " and " -4 le x le 4` Therefore, domain is `[-4,-pi] cup [0,pi].` |
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