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Find the electric potential for an electric field 3units at a distance of 2m.(a) 9(b) 4(c) 6(d) 3/2I had been asked this question in homework.Origin of the question is Relation of E,D,V in chapter Electrostatic Fields of Electromagnetic Theory

Answer» CORRECT choice is (c) 6

The EXPLANATION: The electric field intensity is the RATIO of electric potential to the distance. E = V/d. To get V = E X d = 3 X 2 = 6units.


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