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Find the energy liberated in the course of the thermonuclear reaction ""_(3)Li^(6)+""_(1)H^(2)to2""_(2)He^(4) Do the calculations for one nucleus and for one nucleon. Compare with the energy liberated in the process of fission of uranium. |
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Answer» `Deltaepsi=(6.01513+2.01410-2xx4.00260)xx931.5=22.4MeV` The energy RELEASE PER nucleon is 22.4/8 = 2.8 MeV. This is three times as much as is released in FISSION of URANIUM : 200/235 = 0.85 MeV per nucleon. |
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