1.

Find the energy of photon of electromagnetic radiation of wavelength 200 Å.A. `1.76xx10^(-18)J`B. `0.99xx10^(-18)J`C. `0.54xx10^(-18)J`D. `0.63xx10^(-18)J`

Answer» (b) `E=(hc)/(lambda)=(6.62xx 10^(-34)xx3xx 10^(8))/(2000xx10^(-10))=0.0099xx 10^(-16)`
`E=0.99xx 10^(-18) J`


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