Find the energy of the reaction `Li^(7)+prarr2He^(4)` if the binding energies per nucleon in `Li^(7)` and `He^(4)` nuclei are known to be equal to `5.60` and `7.06 MeV` respectively.

Find the energy of the reaction `Li^(7)+prarr2He^(4)` if the binding e

1.	Find the energy of the reaction `Li^(7)+prarr2He^(4)` if the binding energies per nucleon in `Li^(7)` and `He^(4)` nuclei are known to be equal to `5.60` and `7.06 MeV` respectively.
Answer» The energy of reaction `Li^(7)+prarr2He^(4)` is , `2xxB.E of He^(4)-B.E of Li^(7)` `8epsilon_(alpha)-7epsilon_(Li)= 8xx7.06-7xx5.60= 17.3MeV`

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Find the energy of the reaction `Li^(7)+prarr2He^(4)` if the binding energies per nucleon in `Li^(7)` and `He^(4)` nuclei are known to be equal to `5.60` and `7.06 MeV` respectively.

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