Find the equation fo simple harmonic motion of a particle whose amplitude is 0.04 and whose frequency is 50 Hz . The initial phase is `pi//3` . Assume that motion of particle is started from mean position.

Find the equation fo simple harmonic motion of a particle whose amplit

1.	Find the equation fo simple harmonic motion of a particle whose amplitude is 0.04 and whose frequency is 50 Hz . The initial phase is `pi//3` . Assume that motion of particle is started from mean position.
Answer» From equation of SHM , `x=A "sin"(omegat+phi)` Here, `A=0.04 m,v=50 Hz , phi=(pi)/(3)` `therefore x=0.04 "sin"(2pi xx 50t+(pi)/(3)) " "(because omega=2piv)` or `x=0.04 "sin"(100pit+(pi)/(3))`

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Find the equation fo simple harmonic motion of a particle whose amplitude is 0.04 and whose frequency is 50 Hz . The initial phase is `pi//3` . Assume that motion of particle is started from mean position.

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