Find the equation of a curve which passes through the origin and whose – InterviewSolution

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1.	Find the equation of a curve which passes through the origin and whose differential equation is `(dy)/(dx) =e^(x) sin x`.
Answer» Correct Answer - `2y=e^(x)(sinx-cosx)+1` Use the formula `inte^(ax)sin bx dx = (e^(ax)(asinx bx-b cosbx))/((a^(2)+b^(2))).` Put `a = 1 and b = 1`.

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