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Find the equation of a line passing through point (-2,3) and perpendicular to 7x + 2y + 3 = 0. |
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Answer» Here, `(x_(1) , y_(1)) = (-2,3) , a = 7` and b = 2 . `therefore` Equation of the line perpendicular to 7x + 2y + 3 = 0 and passing through `(-2,3)` is `b(x - x_(1)) - a(y_ - y_(1)) = 0` . That is , 2(x+2) - 7(y-3) = 0 `implies 2x - 7y + 25 = 0` . Hence the required equation of the line is 2x - 7y + 25= 0 . |
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