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Find the equation of a line passing through the point (-3,2) and parallel to line 4x - 3y - 7 = 0 . |
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Answer» Here `(x_(1) , y_(1)) = (-3 , 2) , a = 4` and b = -3 `therefore` Equation of the line passing through P(-3,2) and parallel to 4x - 3y - 7 = 0. `a(x-x_(1)) + b(y-y_(1)) = 0` `implies 4(x + 3) - 3(y-2) = 0` `implies 4x - 3y + 18 = 0` . Hence . the equation of the required line is 4x - 3y + 18 = 0. |
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