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Find the equation of a line passing through the points (-1,1) and (2,-4) |
Answer» Let the given points be A(-1,1) and (2,-4) . We know that the equation of a line passing through the points. `(x_(1),y_(1)) and (x_(2),y_(2))"is given by"((y-y_(1)))/((x-x_(1)))=((y_(2)-y_(1)))/((x_(2)-x_(1)))` Here, `x_(1)=-1, y_(1)=1, x_(2)=2 and y_(2)=-4`. So, the equation of a line passing through the given points is `((y-1))/(x-(-1))=((-4-1))/(2-(-1)) Leftrightarrow ((y-1))/((x+1))=(-5)/(3)` `Leftrightarrow 3(y-1)=-5(x+1)` `Leftrightarrow 5x+3+2=0`. Hence, the required equation is 5x+3y+2=0. |
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