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Find the equation of a parabola whose focus and vertex are (0, 0) and (0, 2) respectively. |
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Answer» The focus (0,0) and vertex (0,2), of the parabola lie on Y-axis. Produce SA + AZ =2+2=4 Draw a perpendicular ZM from Z to the axis of parabola. ZM is the directrix of the parabola whose equation is y-4=0. Let P(x,y) be any point on the parabola. Now the equation of parabola PS=PM `sqrt((x-0)^(2)+(y-0)^(2))=y-4` `rArr" "x^(2)+y^(2)=(y-4)^(2)` `rArr" "x^(2)+y^(2)=y^(2)-8y+16` `rArr" "x^(2)=-8(y-2)`. |
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