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Find the equation of a plane containing the line of intersectionof the planes `x+y+z-6=0a n d2x+3y+4z+5=0`passing through `(1,1,1)`.A. `20x+23y+26z-69=0`B. `20x+26y+23z-69=0`C. `x+y+z-3=0`D. `2x+3y+4z-9=0` |
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Answer» Correct Answer - A The equation of the plane through the line of intersection of the given planes is `(x+y+z-6)+lamda(2x+3y+4z+5)=0` ………..i If it pases through (1,1,1) we have `-3+14lamda=0implieslamda=3//14` Putting `lamda=3//14` in i we obtain the equation of the required plane as `20x+23y+26z-69=0` |
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