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Find the equation of a plane which passes through thepoint (3, 2, 0) and contains the line `(x-3)/1=(y-6)/5=(z-4)/4dot`A. `x-y+z=1`B. `x+y+z=5`C. `x+2y-z=1`D. `2x-y+z=5` |
Answer» Correct Answer - a The required plane is `|[x-3,y-6,z-4],[3-3,2-6,0-4],[1,5,4]|=0` or `|[x-3,y-z-2,z-4],[0,0,-4],[1,1,4]|=0` `("Operating"C_(2)toC_(2)-C_(3))` or `4(x-3-y+z+2)=0` or `x-y+z=1` |
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