1.

Find the equation of a straight line in the plane vecr.vecn =d which is parallel to vecr = veca + lamda vecb and passes through the foot of the perpendicular drawn from point P (veca)to vecr.vecn=d(where vecn .vecb=0).

Answer»

`VECR= VECA+ ((d- veca.vecn)/( n ^(2))) vecn + lamda VECB`
`vecr = veca + ((d - veca.vecn)/(n)) vecn + lamda vecb`
`vecr = veca + ((veca. Vecn -d)/(n ^(2))) vecn + lamda vecb `
`vecr = veca + ((veca.vecn-d)/(n)) vecn+lamda vecb`

Answer :A


Discussion

No Comment Found