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Find the equation of a straight line in the plane vecr.vecn =d which is parallel to vecr = veca + lamda vecb and passes through the foot of the perpendicular drawn from point P (veca)to vecr.vecn=d(where vecn .vecb=0). |
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Answer» `VECR= VECA+ ((d- veca.vecn)/( n ^(2))) vecn + lamda VECB` |
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