1.

find the equation of a straitht line passing through the point p(-5,2) and parallel to the line joining the points Q(3,-2) and R(-5,4)​

Answer»

<P>Answer:

4y+3x+7

Step-by-step EXPLANATION:

let the line be AB

when TWO lines are parallel there slope is same

Q(3,-2)=Q(x,y) &. R(-5,4)=R(x',y')

Slope of QR(M)= (y'-y)÷(x'-x)

=(4-(-2))÷(-5-3)

=6÷(-8)

= -3/4.......

Slope of line AB(M')= -3/4

P(-5,2)=P(x",y") is point on AB

.......,EQUATION of line of AB

(y - y") = M'(x - x")

y-2= -3/4(x-(-5))

4y-8=-3x-15

4y+3x+7......


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