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Find the equation of an ellipse whose eccentricity is 2/3, the latusrectum is 5 and the centre is at the origin. |
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Answer» Correct Answer - `(4x^(2))/81 + (4y^(2))/45 = 1` `(2b^(2))/a = 5 rArr (2a^(2)(1-e^(2)))/a = 5 rArr a = 9/2.` Also, ` b^(2) = (5a)/2 = (5/2 xx 9/2) = 45/4.` |
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