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Find the equation of aplane which is parallel to the plane `x-2y+2z=5`and whose distance fromthepoint `(1,2,3)`is 1. |
Answer» The equation of the plane parallel to `" "x-2y+2z=5` is `x-2y+2z+k=0" "` (i) Now, according to the equation, `" "(1-4+6+k)/(sqrt(9))=pm1` `" "k+3=pm3 rArr k=0 or -6` Then `x-2y+2z-6=0 or x-2y+2z=6` |
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