1.

Find the equation of aplane which is parallel to the plane `x-2y+2z=5`and whose distance fromthepoint `(1,2,3)`is 1.

Answer» The equation of the plane parallel to
`" "x-2y+2z=5` is `x-2y+2z+k=0" "` (i)
Now, according to the equation,
`" "(1-4+6+k)/(sqrt(9))=pm1`
`" "k+3=pm3 rArr k=0 or -6`
Then `x-2y+2z-6=0 or x-2y+2z=6`


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