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Find the equation of circumcircle of the triangle whose sides are `2x +y = 4,x + y = 6 and x +2y=5`. |
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Answer» First we will find the co-ordinates of the vertices of a triangle `:.` On solving two-two equations, we get the vertices as `(-2,8),(7,-1) and (1,2)` Let the equation of circle be `x^(2)+y^(2)+2gx+2fy+c=0`....(1) This circle passes through the point `(-2,8)` `4+64 -4g +16f + c=0` `rArr -4g +16f +c = -68` .....(2) This circle passes through the point `(7,-1)` `49 +1 +14g-2f +c=0` `rArr 14g - 2f +c = -50` ....(3) This circle passes through the point (1, 2) `1+4+2g+4f +c=0` `rArr2g+4f+c=-5`....(4) From eqs. (2),(3) and (4) `g=-(17)/(2),f=-(19)/(2),c=50` From eq. (1), equation of circle `x^(2)+y^(2)-17x-19y+50=0`. |
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