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Find the coordinates of the foci, the vertices, the eccentricity and the length of the latus rectum of the Hyperbola `(y^(2))/(9)-(x^(2))/(27)=1` |
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Answer» `(y^(2))/(9)-(x^(2))/(27)=1` which is the equation of conjugate hyperbola Here, `b^(2)=9anda^(2)=27` `rArr" "b=3anda=3sqrt(3)` Coordinates of vertices `-=(0,pmb)-=(0,pm3)` Eccentricity `e=sqrt(1+(a^(2))/(b^(2)))=sqrt(1+(27)/(9))=2` Coordinates of foci `-=(0,pmbe)` `-=(0,pm3xx2)` `-=(0,pm6)` Length of latus rectum `=(2a^(2))/(b)=(2xx27)/(3)=18` |
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