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                                    Find the equation of family of planes through the line of intersection of the planes 3x – y + 2z = 4 and x + y + z = 2 which is passing through (2, 2, 1)? | 
                            
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Answer»  The equation of the family of planes through the line of intersection of planes 3x – y + 2z = 4 and x + y + z = 2 is, (3x – y + 2z – 4) + k(x + y + z – 2) = 0 ……(1) If it passes through (2, 2, 1) then, (6 – 2 + 2 – 4) + k(2 + 2 + 1 – 2) = 0 k = –\(\cfrac23\) Substituting k = – \(\cfrac23\)in eq.(1) We get, 7x – 5y + 4z = 0 as the equation of the required plane.  | 
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