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Find the equation of plane parallel to 2x – 3y + z = 0 and passing through the point (1, – 1, 2)? |
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Answer» Given Eq. of plane is 2x – 3y + z = 0 …… (1) We know that equation of a plane parallel to given plane (1) is 2x – 3y + z + k = 0 …… (2) As given that , plane (2) is passing through the point (1, – 1, 2) so it satisfy the plane (2), 2(1) – 3( – 1) + (2) + k = 0 2 + 3 + 2 + k = 0 7 + k = k = – 7 put the value of k in equation (2), 2x – 3y + z – 7 = 0 So, equation of the required plane is , 2x – 3y + z = 7 |
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