1.

Find the equation of the plane passing through the points A(1, 1, 2) and B(2, -2, 2) and perpendicular to the plane 6x – 2y + 2z = 9.

Answer»

Plane passes through (1,1,2) and (2,- 2,2), 

A(x - 1) + B(y -1) + C(z - 2) = 0 (1) 

A(x - 2) + B(y + 2) + C(z - 2) = 0 (2) 

Subtracting (1) from (2), 

A(x - 2 - x + 1) + B(y + 2 - y-1) = 0 

A - 3B = 0 (3) 

Now plane is perpendicular to 

6x - 2y + 2z = 9 6A - 2B + 2C = 0 (4) 

Using (3) in (4) 

18A - 2B + 2C = 0 

16B + 2C = 0 

C = - 8B 

Putting values in equation (1) 

3B(x - 1) + B(y + 2) - 8B(z - 2) = 0 

B(3x - 3 + y + 2 - 8z + 16) = 0 

3x + y - 8z + 15 = 0



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