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Find the equation of line parallel to the y-axis and drawn through the point of intersection of `x 7y+ 5 = 0`and `3x+y 7 = 0`. |
Answer» The equation of any line through the point of intersection of the given line is of the form `(x-7y+5)+k(3x+y-7)=0` `Rightarrow (1+3k)x+(k-7)y+(5-7k)=0........(i)` If the line is parallel to y-axis then coefficient of y should be 0,i.e. k-7=0, which gives k=7. Substituting k=7 in (i), we get 22x-44=0 `therefore` x-2=0, which is the required equation. |
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