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find the equation of straight line passing through (1,1) and which are at a distance of 3 units from (-2,3). |
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Answer» Step-by-step EXPLANATION: (x+2)²+(y+3)²=(3)² x2+4x+4+y²+6y+9=9 x²+y²+4x+6y+4=0 tan =m=3-1/-2-1 m=2/-3 (y-1)=2/-3(x-1) -3y+1=2x-2 -3y+1-2x+2 -2x-3y+3 2x+3y-3=0 |
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