InterviewSolution
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Find the equation of the hyperbola whose foci are (± 5, 0) and the conjugate axis is of length 8 ?1. \(\frac{{{x^2}}}{{{9}}} - \frac{{{y^2}}}{{{16}}} = 1\)2. \(\frac{{{x^2}}}{{{9}}} - \frac{{{y^2}}}{{{7}}} = 1\)3. \(\frac{{{x^2}}}{{{25}}} - \frac{{{y^2}}}{{{16}}} = 1\)4. None of these |
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Answer» Correct Answer - Option 1 : \(\frac{{{x^2}}}{{{9}}} - \frac{{{y^2}}}{{{16}}} = 1\) CONCEPT: The properties of a rectangular hyperbola \(\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1\) are:
CALCULATION: Here, we have to find the equation of the hyperbola whose foci are (± 5, 0) and the conjugate axis is of length 8. By comparing the foci (± 5, 0) with (± ae, 0) ⇒ ae = 5 ∵ Length of the conjugate axis is given by 2b ⇒ 2b = 8 ⇒ b = 4 As we know that, eccentricity of a hyperbola is given by \(e = \frac{{\sqrt {{a^2} + {b^2}} }}{a}\) ⇒ a2e2 = a2 + b2 ⇒ 25 = a2 + 16 ⇒ a2 = 9 So, the equation of the required hyperbola is \(\frac{{{x^2}}}{{{9}}} - \frac{{{y^2}}}{{{16}}} = 1\) Hence, option A is the correct answer. |
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