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Find the equation of the line drawn through the point interseciton of the line 4x-3y+7=0 and 2x+3y+5=0 and passing through the point (-4,5). |
Answer» The equation of any line through the point of intersection of the given line is of the form. `(4x-3y+7)+k(2x+4y+5)=0` `Rightarrow (4+2k)x+(3k-3)y+(5k+7)=0......(i)` If it passes through the point (-4,5), we have `(4+2k)(-4)+(3k-3).5+(5k+7)=0` `Rightarrow -16-8k+15k-15+5k+7=0 Rightarrow 12k=24 Rightarrow k=2` Substituting k=2 in (i), we get 8x+3y+17=0, which is the required equation |
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