1.

Find the equation of the line drawn through the point interseciton of the line 4x-3y+7=0 and 2x+3y+5=0 and passing through the point (-4,5).

Answer» The equation of any line through the point of intersection of the given line is of the form.
`(4x-3y+7)+k(2x+4y+5)=0`
`Rightarrow (4+2k)x+(3k-3)y+(5k+7)=0......(i)`
If it passes through the point (-4,5), we have
`(4+2k)(-4)+(3k-3).5+(5k+7)=0`
`Rightarrow -16-8k+15k-15+5k+7=0 Rightarrow 12k=24 Rightarrow k=2`
Substituting k=2 in (i), we get
8x+3y+17=0, which is the required equation


Discussion

No Comment Found

Related InterviewSolutions