Find the equation of the line passing through the point (2,-5) and parallel to the line 2x-3y=7.

Find the equation of the line passing through the point (2,-5) and par

1.	Find the equation of the line passing through the point (2,-5) and parallel to the line 2x-3y=7.
Answer» We have `2x-3y=7 Rightarrow y=(2)/(3)x=(7)/(3)` `therefore` slope of the given line=`(2)/(3)` and the slope of a line parallel to the given line=`(2)/(3)` . Now, the equation of the line slope `(2)/(3)` and passing through the points (2,-5) is given by `(y-(-5))/(x-2)=(2)/(3) Rightarrow (y+5)/(x-2)=(2)/(3)" "[therefore ((y-y_(1)))/((x-x_(1)))=m]` `Rightarrow 3(y+5)=2(x-2)` `Rightarrow 2x-3y-19=0`, which is the required equation.

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Find the equation of the line passing through the point (2,-5) and parallel to the line 2x-3y=7.

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