1.

Find the equation of the line passing through the point P(4, -5) and parallel to the line joining the points A(3, 7) and B(-2, 4).

Answer» Correct Answer - 3x-5y-37=0
Slope of the given line=slope of AB=`(4-7)/(-2-3)=(3)/(5)`, Thus, m`=(3)/(5)`
`therefore` required equation is `(y+5)/(x-4)=(3)/(5) Leftrightarrow 3x-5y-37=0`.


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