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Find the equation of the line passing through the point P(-3,5) and perpendicular to the line passing through the points A(2, 5) and B(-3, 6).

Answer» Correct Answer - 5x-y+20=0
Slope of AB=`m_(1)=(6-5)/(-3-2)=(-1)/(5)`
Now, `m_(1)m_(2)=-1 Leftrightarrow (-1)/(5)xxm_(2)=-1 Leftrightarrow m_(2)=5`
`therefore` required equation is `(y-5)/(x+3)=5 Leftrightarrow 5x-y+20=0`.


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