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Find the equation of the line through the intersection of `5x-3y=1`and `2x-3y -23= 0`and perpendicular to the line `5x - 3y -1 =0`. |
Answer» Let `m1` be the slope of required line. `m2=5/3`(slope of given line) As, `m1*(m2)=-1` so, `m1=-3/5`.On Solving given two equations, `5x-3y-1=0, 2x+3y-23=0` We get,`(x,y)=(24/7, 113/7)`. Equation of required line,`(y-113/7)=(-3/5)(x-24/7)` `63x+105y-781=0` |
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