1.

Find the equation of the line through the intersection of `5x-3y=1`and `2x-3y -23= 0`and perpendicular to the line `5x - 3y -1 =0`.

Answer» Let `m1` be the slope of required line.
`m2=5/3`(slope of given line)
As, `m1*(m2)=-1`
so, `m1=-3/5`.On Solving given two equations,
`5x-3y-1=0, 2x+3y-23=0`
We get,`(x,y)=(24/7, 113/7)`.
Equation of required line,`(y-113/7)=(-3/5)(x-24/7)`
`63x+105y-781=0`


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