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Find the equation of the line through the intersection of the lines `2x+ 3y 4 = 0` and `x - 5y= 7`that has its x-intercept equal to ` 4`. |
Answer» Equation of the required line can be given as `2x+3y-4+k(x-5y-7) = 0` `(2+k)x+(3-5k)y - (4+7k) = 0->(1)` As, x- intercept is given, we can put `y = 0` `:.(2+k)x = 4+7k` `=> (2+k)(-4) = 4+7k` `=>-8-4k = 4+7k=>k = -12/11` So, putting value of `k` in (1), we get the required equation. `(2-12/11)x+(3+60/11)-(4-84/11) = 0` `=>10x+93y+40 = 0`, which is the required equation. |
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