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Find the equation of the line which passes through the point (22,-6) and whose intercept on the x-axis exceeds the intercept on the y-axis by 5. |
Answer» Correct Answer - 6x+11y-66=0 or x+2y-10=0 Let the required equation be `(x)/(a+5)+(y)/(a)=1` Since it passes through (22,-6), we have `(22)/(a+b)-(6)/(a)=1` This gives `a^(2)-11a+30=0 Rightarrow (a-6)(a-5)=0 Leftrightarrow a=6 or a=5` So, the required equations are `(x)/(11)+(y)/(6)=1 or (x)/(10)+(x)/(5)=1` |
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