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Find the equation of the line y-intercept is -3 and which is perpendicular to the line `3x-2y+5=0`

Answer» `3x-2y+5=0 Rightarrow y=(3)/(2)x+(5)/(2)`
`therefore` slope of the given time=`(3)/(2)`
`therefore` slope of a line perpendicular to the given line `=(-2)/(3)" "[therefore m_(2)=(-1)/(m_(1))]`
Now, the equatoin of a line with slope `(-2)/(3)` and y-intercept -3 is given by `y=(-2)/(3)x-3" "[therefore y=mx+c]`
`Rightarrow 2x+3y+9=0`, which is the required equation.


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