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Find the equation of the perpendicular bisector of the line segmentjoining the points `A(2,3)`and `B(6,-5)dot` |
Answer» The slope of AB is given by `m = (-5-3)/(6-2) = -2` Therefore, the slope of the line perpendicular to AB is ` -(1)/(m) = (1)/(2)` Let P be the midpoint of AB. Then, the coordinates of P are `((2+6)/(2) , (3-5)/(2))`, i.e., (4,-1) Thus, the required line passes through P(4,-1) and has slope 1/2. So, its equation is `y+1 = (1)/(2)(x-4) " " [("Using " y-y_(1) = m(x_(1)-x_(1))]` or x-2y-6 = 0 |
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