1.

find the equation of the straight line through the point of intersection of the lines 2y = 3 3 and use-y + 7 =0 and which & Parallel to 5x+4y = 13.​

Answer»

Answer:

Let the EQUATION of the line having equal INTERCEPTS on the axes be 

ax+ay=1

x+y=a....(1)

On solving equation 4x+7y−3=0 and 2x−3y+1=0  we OBTAIN x=131andy=135

∴{131,135} is the point of intersection of the two given lines.

Since equation (1) PASSES through point {131,135}

{131+135}=a

⇒a=136

∴ Equation (1) becomes x+y=136,i.e.,13x+13y=6

Thus the required equation of the line is 13x+13y=6


Discussion

No Comment Found

Related InterviewSolutions