InterviewSolution
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InterviewSolution
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Find the equation of theline passing through the intersection `(-1,2,3)`and perpendicular to thelines `(x-1)/2=(y-2)/(-3)=(z-3)/4a n d(x-4)/5=(y-1)/2=zdot`and also through the point `(2,1,-2)dot` |
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Answer» Intersection point of the lines `" "(x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-4)/(5)=(y-1)/(2)=z` is (-1, -1, -1) (on solving). Therefore, the equation of the line passing through the points(-1, -1, -1) and (2, 1, -2) is `(x+1)/(3)=(y+1)/(2)=(x+1)/(-1)`. |
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