InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Find the equation of theplane perpendicular to the line `(x-1)/2=(y-3)/(-1)=(z-4)/2`and passing through the origin. |
|
Answer» Any plane passing through the origin is `a(x-0) +b (y-0)+c(z-0)=0` This is perpendicular to the given line. Therefore, the normal to the plane is parallel to the give line. Thus, `" "(a)/(2)=(b)/(-1)=(c)/(2)` Therefore, the required plane is `" "2(x-0)-1(y-0)+2(z-0)=0` or `" " 2x-y+2z=0` |
|