InterviewSolution
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InterviewSolution
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Find the equation of theplane which passes through the point `(12,3)`and which is at the maxixumdistance from the point `(-1,0,2)dot` |
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Answer» The plane passes through the point `A(1, 2, 3)` and is at the maximum distance from the point `B(-1, 0, 2)`, then the plane is perpendicular to line `AB`. Therefore, the direction ratios of the normal to the plane are 2, 2 and 1. Hence, the equation of the plane is `" "2(x-1)+2(y-2)+1(z-3)=0` or `" "2x+2y+z=9` |
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