1.

Find the equationof the line through the intersection of the lines `2x+" "3y " "4" "=" "0`and `x " "5y=" "7`that has its x-intercept equal to `" "4`.

Answer» The given line are 2x+3y-4=0 and x-5y+7=0. The equation of any line through the intersection of given line is of the form `(2x+3y-4)+k(x-5y+7)=0`
`Rightarrow (2+k)x+(3-5k)y+(7k-4)=0.....(i)`
If this line has x-intercept-4, then the point (-4,0) lies on (i),
`therefore (2+k)(-4)+(7k+4)=0 Rightarrow -8-4k+7k-4=0`
`Rightarrow 3k=12 Rightarrow k=4.`
Substituting k=4 in (i), we get
6x-17y+24=0, which is the required equation.


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