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Find the equationof the line through the intersection of the lines `2x+" "3y " "4" "=" "0`and `x " "5y=" "7`that has its x-intercept equal to `" "4`. |
Answer» The given line are 2x+3y-4=0 and x-5y+7=0. The equation of any line through the intersection of given line is of the form `(2x+3y-4)+k(x-5y+7)=0` `Rightarrow (2+k)x+(3-5k)y+(7k-4)=0.....(i)` If this line has x-intercept-4, then the point (-4,0) lies on (i), `therefore (2+k)(-4)+(7k+4)=0 Rightarrow -8-4k+7k-4=0` `Rightarrow 3k=12 Rightarrow k=4.` Substituting k=4 in (i), we get 6x-17y+24=0, which is the required equation. |
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