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Find the equations of het planes parallel to the plane `x+2y-2z+8=0`which are at distance of 2 units from the point `(2,1,1)dot` |
Answer» Let equation of plane parallel to plane `x+2y-2z+18=0` `x+2y-2z+lambda = 0 "….."(1)` Perpendicular distance from `(2,1,1)` to this plane `|(2+2-2+lambda)/(sqrt(1+4+4))|=|(lambda+2)/(3)|` Given that `|(lambda+2)/(3)| = 3 rArr (lambda+2)/(3) = +-3` `rArr lambda+2=+-9` `rArr lambda = 7` or ` lambda = - 11` From eq. (1) Required equations of planes `x+2y-2z+7=0` or `x+2y-2z-11 = 0`. |
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