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Find the equations of the line which passes through the point `(3,4)`and the sum of its intercepts on the axes is`14`. |
Answer» Let the intercepts made by the line on the x-axis and y-axis be a and (14-a) respectively. Then, its equation is `(x)/(a)+(y)/((14-a))=1" "["intercept form"]` Since it passes through the point (3,4), we have `(3)/(a)+(4)/((14-a))=1 Leftrightarrow 3(14-a)+4a=a(14-a)` `Leftrightarrow a^(2)-13a+42=0 Leftrightarrow (a-6)(a-7)=0` `Leftrightarrow a=6 or a=7` `"Now," a=b Leftrightarrow 14-6=8` `"And" a=7 Leftrightarrow 14-7=7` So, the required equation is `(x)/(6)+(y)/(8)=1 or (x)/(7)+(y)/(7)=1` `i.e. 4x+3y-24=0 or x+y-7=0` |
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