Find the equations of the lines, which cut-off intercepts on the axeswhose sum and product are `1`and `-6`, respectively.

Find the equations of the lines, which cut-off intercepts on the axesw

1.	Find the equations of the lines, which cut-off intercepts on the axeswhose sum and product are `1`and `-6`, respectively.
Answer» Let the required equation be `(x)/(a)+(y)/(b)=1`. Then x-intercept=a and y-intercept-b `therefore a+b…..(i)` and ab=-……..(ii) Putting `b=(-6)/(a)` from (ii) in (i), we get `a-(6)/(a)=1 Leftrightarrow a^(2)-a-6=0 Leftrightarrow (a-3)(a+2)=0` `Leftrightarrow a=3 or a=-2` `"Now", a=3 Leftrightarrow b=(1-a)=(1-3)=-2` `"And", a=-2 Leftrightarrow b=(1-a)=(1+2)=3` `therefore` the required equation is `(x)/(3)+(y)/(-2)=1 or (x)/(-2)+(y)/(3)=1` `i.e. 2x-3y-6=0 or 3x-2y+6=0`

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Find the equations of the lines, which cut-off intercepts on the axeswhose sum and product are `1`and `-6`, respectively.

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