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Find the equations of the lines which pass through the origin and areinclined at an angle `tan^(-1)m`to the line `y=m x+cdot` |
Answer» Correct Answer - `y =0, y = (2mx)/(1-m^(2))` Angle between both the lines is `"tan"^(-1)m+- "tan"^(-1)m = "tan"^(-1) (2m)/(1-m^(2)) or "tan"^(-1)0` Therefore, the equations of the lines are `y=0, y= (2mx)/(1-m^(2))` |
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