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Find the equivalent capacitance between P and Q for the configuration shown below in the figure (a). |
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Answer» SOLUTION :The capacitors 1 `mu` F and `3muF` are connected in parallel and `6muF` and `2MUF` are ALSO separately connected in parallel . So these parallel COMBINATIONS reduced to equivalent single capacitances in their respective positions as shown in the figure (b) . `C_(eq)=1muF+3muF=4muF` `Ceq=6muF+2muF=8muF` From the figure (b) we infer that the tow `4muF` capacitors are connected in series and the TWO `8muF` capatiors are connected in series . By using formula for the series we can reduce to their equivalent capacitances as shown in figure (c) . `(1)/(C)=(1)/(4)+(1)/(4)=(1)/(2) implies C_(eq) =2muF "and " (1)/(C_(eq))=(1)/(8)+(1)/(8)=(1)/(4)implies C_(eq)=4muF` From the figure (c) we infer that `2muF` and `4muF` are connected in parallel . So the equivalent capacitance is given in the figure (d) . `(C_(eq)=2muF+4muF=6muF` Thus the combination of capacitances in figure (a) can be replaced by a single capacitance `6muF.` |
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