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Find the equivalent resistance between A & B in the given network. |
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Answer» Solution :When hypothetical battery is connected to the given circuit the current DISTRIBUTION will be as SHOWN. `(1)/(R_(AB))=((R+3r))/(r(r+3R))+(1)/(r )` `=(R+3r+r+3R)/(r(r+3R))` `rArr R_(AB)=(r(r+3R))/(4(R+r))` 
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